lim,n reaches infinity that ( 1 + 1/n ) =? ,what do you see?

Answer 1

if 'a' is a real positive number so ;
lim (a / x) = (a/∞) = 0
x -> ∞

Here we have ;
lim (1 +1/n) { we must find Right lim and Left lim} so we have
n -> ∞

▪lim (1 +1/n) = ( 1 +(1/+ ∞)) = (1 + 0 )= +1 { Right lim}
n -> + ∞

▪lim (1 +1/n) = (1 +(1/- ∞)) = (1 + 0 )= +1 { left lim }
n -> - ∞

Good Luck.

Answer 2

1

Answer 3

1

Answer 4

If n reaches infinity 1/n reaches 0
=> lim n->oo (1+1/n) = 1

The line f(n) = 1 is called a horizontal asymptote.
As n reaches infinity, the function f(n)=(1+1/n) approaches this asymptote from the upper side.

Answer 5

( 1 + 1/n ) = ?
( 1 + 1/∞ ) =
( 1 + 0 ) = 1

Answer 6

since n reaches infinity it becomes lim (1+0) which is 0 again

Answer 7

if you isolate the different parts of the equation then you will find it easier to see whatis happening

for n=1 we get 1 + 1/1

the initial 1 is constant then the n factor is variable

so if we look at what happens to 1/n as n increases

n=1 then 1/n=1

n=2 then 1/n= 0.5

n=10 then 1/n = 0.1

so as n increases then 1/n tends towards zero

hence the limit of (1 + 1/n) as n tends towards zero we get towards 1+ 0(+)

this means that overall we tend towards a value of 1 from above as n increases towards infinity

Answer 8

The problem you present must have an error, since the solution is so simple (when n-> infinty, 1/n -> 0). I suspect what you really are looking for is

lim(n->inf) (1+1/n)^n

This is the definition of e, the base of the natural logarithms.

Answer 9

infinity is my friend, i have a wallet size picture of hm, want to see it

here it is ∞