What's the best way to solve the expression (1999^2000)/5? What's the answer in integer form?

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What's the best way to solve the expression (1999^2000)/5? What's the answer in integer form?

2006-09-11 18:12:14 · 2 answers · asked by E. B. W 1 in Education & Reference ➔ Homework Help

2 answers

Take the logarithm of the numerator and denominator. You can then subtract the bottom from the top. Get your calculator out and then plug, chug, and crank.

You should get:

2000log1999 - log 5 = ?

2006-09-11 18:22:15 · answer #1 · answered by Anonymous · 0⤊ 0⤋

y=(1999^2000)/5
take logarithm on both sides
log y=2000 log 1999 - log 5
calculate right hand side and take antilog to get y, the actual value

2006-09-12 01:22:40 · answer #2 · answered by friend 3 · 0⤊ 0⤋