if f(x) = u(x) / v(x)
f'(x) = ( u'(x) (v(x) - v'(x) u(x) / [ v(x^2)]
now if u = -x & v = 10
so we have ;
f '(x) = [-1*(10) - 0 *(-x)] / (10)^2
f '(x) = -10 / 100 = -1/10 = - 0.1
It's your correct answer.
Good Luck
2006-09-12 08:01:25
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answer #1
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answered by sweetie 5
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-1/10
2006-09-12 01:09:00
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answer #2
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answered by free aung san su kyi forthwith 2
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-1/10
2006-09-12 00:36:12
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answer #3
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answered by saby 2
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-1/10
2006-09-12 00:33:13
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answer #4
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answered by Anonymous
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Dewd....... You are in terminally deep sh|t.
This is y = -x/10 = (-1/10)*x which is in the form y = kx. The derivative of y = kx is dy/dx = k so, in this case,
dy/dx = -1/10
Doug
2006-09-12 00:36:34
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answer #5
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answered by doug_donaghue 7
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this can be re-written as -1/10x^1
use the power rule as explained in previous question
(1)*(-1/10)x^(1-1)=
-1/10
2006-09-12 00:36:36
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answer #6
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answered by tplanningstages 1
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This one is really simple .. you should learn how to compute derivitives
y'=-1/10
2006-09-12 00:23:10
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answer #7
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answered by priestlake22 2
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