y=e^x - x , then find the stationary point of y?

3 ⤊

2006-09-11 17:18:31 · 4 answers · asked by free aung san su kyi forthwith 2 in Science & Mathematics ➔ Mathematics

For stationary point, f'(x) = 0

y = f(x) = e^x - x
f'(x) = e^x - 1 = 0
e^x = 1
x = log(1)
x = 0

Dr Pratt.

2006-09-11 21:05:50 · answer #1 · answered by Mujaahid 3 · 1⤊ 0⤋

Stationary point(s) occurs when f'(x) = 0
y = f(x) = e^x - x
f'(x) = e^x - 1 = 0
e^x = 1
x = 0

2006-09-12 00:38:59 · answer #2 · answered by dactylifera001 3 · 1⤊ 0⤋

dactyfera is right
to find stationary point we find derivatives of this function where y'=0
y = e^x - x
y' = e^x - 1
0 = e^x - 1
e^x = 1
x = 0

2006-09-12 02:32:21 · answer #3 · answered by Anonymous · 1⤊ 0⤋

What means 'stationary point'??

Doug

2006-09-12 00:39:55 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋