hey plz help i hat factoring?

Question

64-z^6

Answer 1

Start with the diff. of 2 squares:

(8+z^3)(8-z^3)

Then use the sum and diff. of cubes formulas:

(2+z)(4-2z+z^2)(2-z)(4+2z+z^2)

Answer 2

64 - z^6 =
-z^6 + 64 =
-(z^6 - 64) =
-(z - 2)(z + 2)(z^2 - 2z + 4)(z^2 + 2z + 4)

Answer 3

recognize this is the difference of two perfect squares:
this means that x² - y² = (x+y)(x-y) you have to be able to recognize this pattern in other situations


so apply the trick
(8 + z³) (8 - z³)