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Ok well I kind of need help on this algebra II questions! Please answer if you are serious!
Ok you’re at a really large school, and there are 1,000 closed lockers in a straight hallway. Devin decides that he’s going to opens every other locker. Bryce decides that he is going to change the state (if its open close it, if it’s closed open it) of every third locker. Ethan decides that he’s going to change the state of every fourth locker. This continues on until the 1,000th locker. Which locker will be open? How many will be closed? Which locker will be open by the end? Thank you so much!

2006-09-11 12:32:23 · 5 answers · asked by Angel 1 in Education & Reference Higher Education (University +)

5 answers

Break down the question....

The first person, Devin, does something to ever other door....so figure it out...
1st door :closed
2nd - open
3rd - closed
4 - open
...etc...
Notice that it is the EVEN number that is open...
Therefore, if this pattern continues, you know that Devin will OPEN the 1000th door, because it is an EVEN number

Next... Bryce changes the state of the every 3rd locker....You don't even have to figure out the state of EVERY locker, just you need to know the 1000th locker...
So... 3 times what is closests to 1000?
3 x 333 = 999 .... so they 999th locker is going to change it's state for SURE...but then that means Bryce will skip over 1000 & 1001 and change door 1002.
That STILL leaves the 1000th door open (remeber, Devin opened it)

Lastly, Ethan is going to close ever 4th locker... welll... does 4 go into 1000 evenly?
Yes it does... 4 X 2500 = 1000...
So that means, Ethan is going to change the state of the 1000th locker... Because it is opened(by Devin), Ethan is going to CLOSE it.

So they final answer at the end, the 1000th door will be CLOSED.

2006-09-11 12:47:44 · answer #1 · answered by theviolet41 6 · 0 0

It's a repeating pattern every 12 lockers (LCM of 2,3,4). Obviously after the first step, half of the lockers will be open (you didn't say whether the first or second would be opened). Let's say that evens are open. After the second step, evens are open exept where evens are multiples of three, which are closed. Also, odds that are also multiples of three are open as well. After the third step, Multiples of four are opposite of former state, so:

1 closed, never changed.
2 open
3 open
4 was opened, but now closed.
5 closed, never changed.
6 was opened, but now closed.
7 closed, never changed
8 opened, now closed
9 opened
10 opened
11 closed, never changed
12 Opened, then closed, then opened.

5/12 are opened. this pattern repeats. 83 full patterns of 12 in 1000 lockers, with a remainder of 4.

83*5=415, + 2 more in the first four lockers in the sequence.

417 are opened, 583 are closed. The second to last locker will be open.

2006-09-11 12:59:01 · answer #2 · answered by Anonymous · 0 0

a million. in view that -a million does no longer include the variable to sparkling up for, bypass it to the right-hand part of the equation with the help of including a million to each part. 9x^(2)=a million 2. Divide every time period contained in the equation with the help of 9. (9x^(2))/(9)=(a million)/(9) 3. Simplify the left-hand part of the equation with the help of canceling the issue-loose aspects. x^(2)=(a million)/(9) 4. Take the sq. root of each part of the equation to eliminate the exponent on the left-hand part. x=~((a million)/(9)) 5. chop up the fraction contained in the novel right into a separate radical expression contained in the numerator and the denominator. a fragment of roots is an analogous as a root of the fraction. x=(a million)/(~(9)) 6. Pull all proper sq. roots out from lower than the novel. accordingly, eliminate the three by using the undeniable fact that's a suitable sq.. x=(a million)/(3) 7. First, change contained in the + area of the to discover the first answer. x=(a million)/(3) 8. next, change contained in the - area of the to discover the 2d answer. x=-(a million)/(3) 9. the comprehensive answer is the outcome of both the + and - parts of the answer. answer: x=(a million)/(3),-(a million)/(3) wish this allows u :)

2016-11-26 02:03:25 · answer #3 · answered by ? 4 · 0 0

the locker that will be open would be 1 &2 the rest closed b/c them are the only 2 that are left alone



I am pretty sure..
(I recieved your e-mail)

2006-09-11 12:45:22 · answer #4 · answered by .::country gurl in a 4X4::. 2 · 0 0

get some paper. draw a chart. not that hard.

2006-09-11 12:46:41 · answer #5 · answered by Anonymous · 0 0

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