a hospital has 25 beds at $400 per day, 152 beds at $330 per day, 317 bed at $ 295 per day, 35 beds at $250 per day, and 18 beds at $1100 per day. what is the average cost of a bed to the nearest dollar? show work.
2006-09-11 12:23:42 · 7 answers · asked by DiaBEEtus 3 in Education & Reference ➔ Homework Help
Add the $ amounts together and then divide by 5.
2006-09-11 12:30:43 · answer #1 · answered by Bluealt 7 · 0⤊ 2⤋
You have to multiply by how many beds before you add....
(400*25)+(152*330)+(317*295)+(35*250)+(1100*18)
10000+50160+93515+8750+19800=182225
182225/547(Number of rooms)=333.14
The Average cost of a room is $333.14
2006-09-11 12:36:52 · answer #2 · answered by dirtyrona_420 1 · 1⤊ 0⤋
400+330+295+250+110=2375
2375/5=475
$475 I think
2006-09-11 12:28:34 · answer #3 · answered by crystalblue129 2 · 0⤊ 1⤋
25X400 + 152X330 + 317X295 + 35X250 + 18X1100 = 182225
Divide that by the number of beds which is 547 and the average cost to the nearest dollar is $333
2006-09-11 12:30:10 · answer #4 · answered by MollyMAM 6 · 1⤊ 0⤋
1. Add all $ figures together.
2. Divide answer by 5
2006-09-11 12:33:55 · answer #5 · answered by axegirl72 2 · 0⤊ 2⤋
divide all the costs by the number of beds, add all the quotients up, then divide by five!
hope this helps!
2006-09-11 13:06:40 · answer #6 · answered by ♥ broken hearted ♥ 2 · 0⤊ 1⤋
Looks like the two "blues" don't know how to do this kind of average - a weighted average.
2006-09-11 12:33:18 · answer #7 · answered by Anonymous · 0⤊ 1⤋