does any one know the answer to this math question?

Question

the sum of two numbers is 77. the larger number is 3 more than the smaller number.
find the numbers?

Answer 1

Easy:

Assume y is the larger number, so y = x+3

You have the basic equation x + y = 77

Now, substitute to get x + x + 3 = 77, and solve for x

Therefore, 2x + 3 = 77
2x = 74

x = 37

and y = x + 3 = 40

Answer 2

Let "L" represent the larger number and "s" represent the smaller number, so

"the sume of two numbers is 77", which is

L + s = 77

"The larger number is 3 more than the smaller number" and that is

L = s + 3

therefore if

L + s = 77, and L = s + 3

than

L + s = 77
(s + 3) + s = 77
2s + 3 = 77
2s = 77 - 3
2s = 74
2s/2 = 74/2
s = 37

L = s + 3
L = 37 + 3
L = 40

Answer 3

77 - 3 = 74
74/2 = 37
37 + 3 = 40

37 + 40 = 77.

Required numbers are: 37 & 40.

Answer 4

77 divided by two gives 38 with double 38 you get 76 one short of 77 so I added 2 to 38 and got 40 and took away 1 from 38 and got 37. 40 is three digits higher than 37. The two added equal 77.

Answer 5

Let x be the small number. So, x + 3 is the large number.

Thusly
"Small number plus big number is 77" translates to
(x) + (x + 3) = 77

Now you have to solve for x. Ask your teacher if you need more help than this.

Answer 6

X+Y=77
X=Y+3
2Y+3=77
2Y=74
Y=37

Answer 7

40, 37

Answer 8

x + y = 77
x=3y
Use these 2 equations, plug what x equals (2nd equation) into the first:
3y+y=77
4y=77
y=77/4
Now plug this back into either of the original equations to find x:
(2nd equation):
x=3y
x=3*(77/4)

Answer 9

45 & 42
45+42 = 77
45-42 = 3