Algebra question help??

Question

OK, so no one else can help me with this problem & the like of this problem ... so if someone could explain this to me, I wouldn't have to ask anymore questionss ....

1. The Ravens won twice as many games as they lost. They played 96 games. How many games did they win??
The directions say to translate each problem into a equation.

Thanks to all who answer in advance!!

Answer 1

Looking at this problem in algebra terms, consider this:

x = games lost by the Ravens

Since they won twice as many as they lost,

2x = games won by the Ravens

If you add up all the games they won and lost, it comes out to the total number of games that they played, so we have the equation:

2x + x = 96

Now, we solve for x:

3x = 96
(Divide both sides by 3)

x = 32.

32 is not the answer though. Remember, the number of games WON by the Ravens is equal to 2x.

So 2*32 = 64.

The Ravens won 64 games.

Hope this is thorough enough for you!

Answer 2

let number of games won = x
number of games won = y

total number of games played = x + y = 96

they won twice as many as they lost that is

x = 2y

therefore, 2y + y = 3y = 96 that is y = 32
x = 96 - y

hence they won 64 games

Answer 3

They won 64 games. = 2 x 96/3

96 games = (games won) + (games lost) ------ 1

Games won = 2 x Games Lost ------------ 2

Subst equation 2 to 1.

Answer 4

It's 64

64 + 32 = 96

Hope this helps : )