English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

nicole measured the length of a room as 11.3m. the room is actually 10.5m long. what is nicoles's percent error

2006-09-11 09:05:10 · 5 answers · asked by soccerstar11 3 in Education & Reference Homework Help

5 answers

Here's how you figure the solution. Take 11.3 (her number) and divide by 10.5 (correct number). You'll come up with 1.0762. (rounded). That means Nicole's number was 107.62% of the actual number, which means she over measured by 7.62%.

Hope this helped.

2006-09-11 09:10:13 · answer #1 · answered by answerman63 5 · 1 0

The percentage error is 100% times the relative error.

relative error = (x'-x)/x

% error = (error/actual value)*100 = ((11.3-10.5)/10.5)*100 = 7.62%

2006-09-11 16:10:18 · answer #2 · answered by bug 2 · 0 0

(11.3-10.5)/10.5*100% = 7.6%

2006-09-11 16:08:51 · answer #3 · answered by Bruce__MA 5 · 0 0

hm...... hold on

Ok, back.

7.6%

(11.3 - 10.5)/10.5 = .076 * 100 = 7.6

2006-09-11 16:07:12 · answer #4 · answered by Anonymous · 0 0

11.3 - 10.5= 0.8 0.8/10.5=7.6%

2006-09-11 16:07:28 · answer #5 · answered by Stephen 3 · 0 0

fedest.com, questions and answers