1st GUY- N. Burleson B. Westbrook M. Muhammad
(Sea - WR) (Phi - RB) (Chi - WR)
FOR
2nd GUY- A. Johnson K. Jones Ma. Jones Mi. Vick
(Hou - WR) (DET- RB) (Jac - WR) (Atl - QB)
1st GUY drops -Marion Barber (DAL- RB)
2006-09-11 09:01:30 · 7 answers · asked by KG 23 1 in Sports ➔ Fantasy Sports
1st guy gets better trade here is why
Burleson is not going anywhere he did luke warm and still does luke warm
Brian westbrook blew up the points hesterday and will continue to do so
M Muhammad the bears are throwing more and M muhammad did well and should have decent season
Vick rarly throws only scores on long runs
k jones has suckly offensive line he aint no barry sanders
mat jones for jacksonville will get you a few points here and there with long ones but not very consistant
2006-09-11 09:06:28 · answer #1 · answered by Anonymous · 0⤊ 0⤋
dropping barber was a mistake. but I would rather recieve players from winning teams as opposed to losing teams such as hou det ....but will westbrook be the dog or the star. He is the one that I think is the hinge to this whole deal If he has a year like he had 2 years ago guy 1 wins if westbrook repeats last year(plus he is very injury prone)guy 2 wins
2006-09-11 16:32:36 · answer #2 · answered by nyker 3 · 1⤊ 0⤋
1st guy. Johnson should be good this year, Matt Jones is a freak, Kevin Jones is okay and Vick is okay. He is only giving up one good player. Overall it's pretty even though.
2006-09-11 16:07:40 · answer #3 · answered by Drunk365 7 · 0⤊ 0⤋
1st guy cause brian is going to get tons of touches cause the eagles only have two good wide recievers and mushin muhammad gets tons of touchdownscause hes the best player on the bears offense.
2006-09-11 16:42:46 · answer #4 · answered by bob 1 · 0⤊ 0⤋
2nd guy gest 2 #1 WR's and a QB that will put up some fantasy points.
2006-09-11 16:23:47 · answer #5 · answered by Adios 5 · 1⤊ 0⤋
Guy 2 - Vick is a madman!
2006-09-11 16:05:07 · answer #6 · answered by TexasLSUTiger 3 · 0⤊ 0⤋
the 2nd guy
2006-09-11 18:01:51 · answer #7 · answered by Tommy D 5 · 0⤊ 0⤋