ok this is a question my math teacher gave me
Bob visited the hardware store he observed the following transactions:
Harris bought 4 for 50 cents
Clark bought 21 for $1
Mike bought 1,134 for $2
and Parker bought 450 for $1.50
what did they buy
2006-09-11 08:45:20 · 6 answers · asked by soccer_player_alex 1 in Science & Mathematics ➔ Mathematics
They bought alphabet boards/cards (not including commas!)
4 = 1 letter
21 = 2 letters.... and so on
This is an old trick!
2006-09-11 08:50:28 · answer #1 · answered by m s 3 · 1⤊ 0⤋
Numbers to go on doors, each costing 50 cents per digit.
Harris bought a 4, Clark bought a 2 and a 1, Mike bought two 1s, a 3 and a 4, and Parker bought a 4, a 5 and a zero.
2006-09-11 09:23:59 · answer #2 · answered by fiat_knox 4 · 0⤊ 0⤋
They bought house address numbers at .50 per digit.
Harris's house address is "4" for a total of .50.
Clark's address is "21" for a total of $1.00.
Etc.
(The comma shouldn't appear on Mike's line).
2006-09-11 08:55:56 · answer #3 · answered by Ronnie 3 · 0⤊ 0⤋
I think m_s is right, eash letter or number in this case, costs 50 cents. Brilliant!
2006-09-11 08:50:53 · answer #4 · answered by trulucks 1 · 0⤊ 0⤋
they bought numbers..like ones that you would put on mailboxes, houses, etc
2006-09-11 08:53:17 · answer #5 · answered by Erika 4 · 0⤊ 0⤋
id say nuts and bolts...
2006-09-11 08:49:37 · answer #6 · answered by sur2124 4 · 0⤊ 0⤋