I got an Algebra Question?

Question

If n/n-1 (times) 1/n (times) n/n+1 = 5/k for positive integers n and k, what is the value of k?

Ok my book say's that the answer to k is 24. How do you get this answer. And I'm expecting you people to know this, I did place this question in the mathmatics section.

Answer 1

k = 5*(n^2 - 1)/n

Answer 2

k = 5 / [n/n-1 x 1/n x n/n+1]

Answer 3

k = 5(n²-1) / n

Answer 4

Please re-state the question. Do you mean
(n/n)-1 or n/(n-1)? It makes huge difference.

likewise for n/n+1

EDIT
There is something wrong with your formula if you are expecting K=24. N does not cancel out.

Answer 5

k/5 = (n+1)(n-1)/n

k = 5(n^2-1)/n

for calculator: k = 5(n-1/n)

Answer 6

I got answers......however I did fail algebra 4 times.

Answer 7

(n/(n-1))(1/n)(n/(n+1)) = 5/k
n/(n^2 - 1) = 5/k
k = 5(n^2 - 1)/n

Answer 8

{n/(n-1)}{1/n}{n/(n+1)| =5/k
Can celling n from numerator and denominator we get
n/(n^2-!)=5/k
Now invert both side
(n^2-1)/n = k/5
or {5(n^2-1)}/n=k

Answer 9

Ask your teacher for help, or go to online tutors where they will tell you how to get to the answer.

Answer 10

n/(n-1)*(1/n)*(n/(n+1)=5/k
n/(n^2-1)=5/k
kn=5n^2-5
k=5(n^2-1)/n