2x + 3y = 6 (for x) linear equation?

Question

I am trying to understand literal equation for the indicated variable can anyone please help?. Thank you

This is what the book is asking "Solve each literal equation for the indicated variable. Then it gives this...
2x + 3y = 6 (for x) Linear equation
I understand that is is asking something odd, but that is what is asking. Sorry if it was confusing earlier. Thanks again.

Answer 1

2x+3y=6
x=( 6-3y ) /2

Answer 2

The original equation is 2x + 3y= 6

Know we add a negative three y to both sides of the equation.

2x + 3y -3y= 6 -3y
And we now have

2x= 6 -3y
Know we want to elimanate the 2 on the left side of the equation so we can solve x alone. We elimanate the 2 by dividing both sides of the equation by 2. So.......

2x/2=6 -3y/2

This will equal out to.........

x= 3 -3y/2

Answer 3

Being a linear equation you would normally solve for y in terms of x (the slope intercept form).

2x + 3y = 6
subtract 2x from both sides and get
3y = -2x + 6
divide both sides by 3 and get
y= -2/3x + 2

then slope would = -2/3 and your y intercept would be 2


Now if that is not what you are looking for and they really just want you to solve for x, then you either have not included all information or they are looking for x in terms of y which is not the usual practice of linear equation math. But just in case:

2x + 3y = 6
subtract 3y from each side and get
2x = -3y + 6
divide both sides by 2 and get
x= -3/2y + 3

Hope it helps

Answer 4

2x + 3y = 6

2x = 6 - 3y

x =(6 - 3y)/2

x = 3 - 3/2 y

Answer 5

2x + 3y = 6
(subtract 3y from both sides)
2x = -3y +6
(divide by two)

x=(-3y+6)/2

Answer 6

2x+3y=6
3y=-2x+6
y=-(2/3)x+6

-(2/3)= slope
6=y intercept