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Find the lowest common factor of 6,8,12 i.e. 24
Now divide the largest four digit number i.e 9999 with 24 you will see the number=416.625 it means we have to find the number which is exactly divisible by 24. That will be 24*416=9984 Now try the number 24*417=10008 which is of five digit. hence the required number is 9984

2006-09-11 08:13:49 · answer #1 · answered by Amar Soni 7 · 0 0

First, split 6, 8 and 12 into products of their prime factors:

6 = 2*3
8 = 2*2*2 = 2^3
12 = 2*2*3 = 2^3*3

Since the largest power of 2 we have here is 2^3 and we also have a 3, the LCM (lowest common multiple) is 2^3*3=8*3=24.

(Also note that, since 12 is a multiple of 6, you can exclude the 6 from this question as everything that is a multiple of 12 is also a multiple of 6)

Now we need to find the highest number between 1000 and 9999 that divides by 24.

Since 10000MOD24=16 then (10000-16)MOD24=0 so the answer is 10000-16=9984

Check: 9984/6=1664
9984/8=1284
9984/12=832

Ans. 9984

QED

2006-09-11 07:47:43 · answer #2 · answered by me 2 · 1 0

To divide by all of those evenly, the number must have 2*2*2*3 as some of its factors. This equals 24. So we just have to find the largest four-digit number that divides evenly by 24. Since 10000 mod 24 = 16, we can take 16 off 10000. So the answer is 9984.

If you like, you can check this here:
http://www.google.ca/search?hl=en&q=10000-%2810000+mod+24%29&meta=

2006-09-11 07:34:21 · answer #3 · answered by Anonymous · 1 0

If I understand your question correctly.

9792

9792 ÷ 6 = 1632
9792 ÷ 8 = 1224
9792 ÷ 12 = 816

Procedure.
9 * 8 * 12 = 576
Now take multiples of the answer.
576 * 1 = 576
576 * 2 = 1152
576 * 3 = 1728

↓ ↓ ↓ ↓

576 * 16 = 9216
576 * 17 = 9792 (highest four digit number).
576 * 18 = 10368

2006-09-11 07:45:34 · answer #4 · answered by Brenmore 5 · 0 0

find a number that is a multiple of 24
6 = 2*3
8 = 2*2*2
12= 2*2*3

You need 2*2*2*3 or 24
__________
24| 10000 = 416 2/3

24 * 416 = 9984

2006-09-11 07:47:40 · answer #5 · answered by bob h 3 · 1 0

Least common multiple is 24. So the answer must be divisible by 24.

Call it x then x = 24*n where n is any integer
When is 24*n>9999? when n >416.625
So n = 416 gives your answer...
x = 24*416=9984

2006-09-11 07:37:49 · answer #6 · answered by Andy S 6 · 1 0

first,the number is a multiple of (6,8,12)=24,because 24 is the smallest number that divides equally with each of these numbers.
So ,the bigest numeber is 24*x.
Nou you give x random values until you find one that is smaller than 9999->24*416=9984

2006-09-11 07:41:51 · answer #7 · answered by ioana v 3 · 1 0

Start with the largest four digit number there is, 9,999, and see if it can be divided by each of those numbers. If not, try 9,998. If not, try 9,997, etc.

2006-09-11 07:34:26 · answer #8 · answered by catintrepid 5 · 1 2

9984.
(9984/6=1664,9984/8=1248,9984/12=832)

2006-09-11 07:52:36 · answer #9 · answered by Anonymous · 0 0

9998...wait thats not rignt....shoot, I hate math

2006-09-11 07:33:35 · answer #10 · answered by greenguy415 3 · 0 1

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