how do you solve x3-1/3x3+ 5/6x3?

Question

x3 is x with an expon' of 3, 1/3 has x with an expon of 3, and 5/6x3 has an expon of 3

Answer 1

this cannot besolved as there is no equation involved
this can only be simplifiedthe LCD will be (6x)^3
when simplified [(6x)^3*x^3-1*2^3+5]/(6x)^3
216x^6-3/216x^3
i have taken the sum as follows from what you have explained
x^3-1/(3x)^3+5/(6x)^3

Answer 2

x^3 - 1/3 x^3 + 5/6 x^3
Since you don't have any parentheses, I am assuming that you are meaning ex. 1/3 times x^3, as opposed to 1/(3x^3).
First, I'd want to get rid of the fractions, so multiply the whole thing by 6, just realize that any solution has also been multiplied by 6.
6x^3 - 2x^3 + 5x^3
Ok, now, each term has an x^3 in it, so you can combine them
(6 - 2 +5) x^3
do the simple math...
9x^3

Answer 3

I'm going to assume you mean:
x^3 - 1/3 * x^3 + 5/6 * x^3

In that case, you can use parenthesis to make it simpler:
(1- 1/3 + 5/6)x^3

Add fractions:
(6/6 - 2/6 + 5/6)x^3
9/6 * x^3

Simplify:
3/2 * x^3