How many 4 digit numeric codes can be created?

Question

You can use the numbers more than one time in the codes

Answer 1

10000

0000 thru 9999 = 10,000 individual numbers

Answer 2

The answer of 10,000 assumes that you can write 0010 and have that count as 4 digits. And also 0000. is this what you intended?

If so, it's not so hard to conceive. You can count the numbers 1 to 9999. 9999 of them, right? Then add in 0000 to make 10,000.

To get the number of 4 digit numbers, starting with 1000, you'd just need to knock out the first 1000 (0 through 999). Then your answer would be 9000.

I hope this helps!

Answer 3

What base?

In base 10, you have ten symbols, so your max would be 10^4, or 10000.

If base 2 (binary), your max would be 2^4, or 16.

If base 16 (hex), your max would be 16^4, or 65,536.

If you wanted to know how high you could count on your fingers and toes in binary, it would be 2^20, 1,048,575 (this is actually a slightly different type of question, since a person probably wouldn't care much about 0, which gives you one less than 2^20)

Answer 4

if you allow 0 (zero) as a number is any position of the code, it would be 10 x 10 x 10 x 10 = 10,000

Answer 5

10^4

Answer 6

99990 is how many combinations there are in a four digit code. thats 10(0-9) multiplied by 9999, the highest four digit code, and together equals the amount of combinations you can get.

Answer 7

9000 if u cant start it with 0
if 0 can be the first digit then 10000

Answer 8

10,000, if you accept 0-9 for each digit.

Answer 9

9999 unless you include 0000

Answer 10

10,000 if you include 0000