2006-09-11 03:25:47 · 18 answers · asked by Anonymous in Education & Reference ➔ Trivia
NO I DON'T THINK SO SORRY:-)
2006-09-18 23:36:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I know MY Barbie and Ken certainly did...when I found out what sex was, my Barbies did it all the time!
2006-09-11 03:29:47 · answer #2 · answered by j_conway83 3 · 0⤊ 0⤋
Nope...Barbie served as Ken's beard
2006-09-11 05:18:02 · answer #3 · answered by SunnySmile83 4 · 0⤊ 0⤋
There is no real proof. I thought they did at first (baby kelly) but it turns out that is was Barbie's little sister.
But then again, Ken is sorta lacking in that department!
2006-09-11 03:28:23 · answer #4 · answered by tui 5 · 0⤊ 0⤋
Well - probably not - if so where are the little Barbie's and Ken's!@
2006-09-11 03:49:44 · answer #5 · answered by nswblue 6 · 0⤊ 0⤋
No, Ken is gay. Barbie was servicing the soldiers of G.I. Joe.
2006-09-11 03:27:25 · answer #6 · answered by Anonymous · 1⤊ 0⤋
Aqua thinks so. Listen to the song "Barbie Girl" on the Aquarium CD and you may, too. But the answer is no. They're plastic, not rubber.
2006-09-11 03:32:42 · answer #7 · answered by Anonymous · 0⤊ 0⤋
No way. Barbie and Ken were suppose to be in high school and high school kids never have sex....ummm...right??
2006-09-11 03:31:36 · answer #8 · answered by Anonymous · 0⤊ 0⤋
have you seen ken ??
barbie was to busy with her barbie jeep and barbie hawaiian beach house
2006-09-11 03:28:33 · answer #9 · answered by Anonymous · 0⤊ 0⤋
No, then men dollies dont have pee pee's so they dry hump each other ... Barbie is far too intelligent fot them ..
2006-09-11 16:59:46 · answer #10 · answered by wickedly_funny66 5 · 0⤊ 0⤋
no if you are talking about sex because they are dolls the only thing they did was make lots of money for their company I hope this answers your question PS if u r talking about my buddy Kenny and barb yes they did how do i know because we went on a double date to the beach and i saw them just like they saw me
Manny
2006-09-11 04:36:17 · answer #11 · answered by mannyalbite 1 · 0⤊ 0⤋