If twice the product of three consecutive prime numbers is 770,then which of the numbers is greatest amongst them?
2006-09-11 02:51:33 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5 * 7 * 11 = 385
Twice the product = (385*2) = 770
Greatest prime among them = 11
2006-09-11 02:55:53 · answer #1 · answered by royalgig 1 · 0⤊ 0⤋
Twice the product of three consecutive primembers is 770 Which numbr is the greatest
5 x 7 x 11 = 385 equals the product
385 x 2 = 770
Twice the product equals 770
11 is the greatest.
2006-09-11 04:31:41 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
first u have to find the number.
lets call the number x
2x=770
therefore x= 770/2
= 385
and the presence of 5 in 385 means that 5x= 385
(u understand that any number that has 5 in it is a multiple of 5 that is 5 times soomething gave the number?)
herefore x = 385/5
ie x = 77
and since the numbers are consecutive prime they are 5, 7 and 11.
hope this helps. cheers!
2006-09-11 03:53:02 · answer #3 · answered by Rare Gem 3 · 0⤊ 0⤋
3*5*11 = 770/2
the answer is 11
2006-09-11 03:48:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋
you need not mention that they are consecutive
now xyz = 770/2 = 10*7*11/2
= 5*7*11
so greatest is 11
2006-09-11 05:25:17 · answer #5 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
It is 11
2006-09-11 02:58:18 · answer #6 · answered by A 4 · 0⤊ 0⤋
if you mean largest/biggest by greatest, then it's the last number of the consecutive numbers...
for example, if the consecutive numbers were 3, 5 and 7...
then 7 is the greatest...
2006-09-11 02:58:19 · answer #7 · answered by Anonymous · 0⤊ 0⤋
770 / 2 = 385
385 / 5 = 77.........77 / 7 = 11
The numbers are 5,7, 11.... the biggest one?, guess! :)
2006-09-11 03:09:50 · answer #8 · answered by axinte_l 1 · 0⤊ 0⤋
11
the prime no.s are 5,7 and 11
2006-09-11 03:40:27 · answer #9 · answered by friend 3 · 0⤊ 0⤋
the biggest one
2006-09-11 02:53:08 · answer #10 · answered by aries4272 4 · 0⤊ 0⤋