1. if m:n=13:11, find m^2-n^2: (m+n)^2?

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2006-09-11 00:14:39 · 3 answers · asked by philip a 1 in Science & Mathematics ➔ Mathematics

Given:
if m:n =13:11, find m²-n²: (m+n)² ?
m²-n² : (m+n)² (Substitute ratio value in).
(13)²-(11)² : (13 + 11)²
169 - 121 : (24)²
48 : 576
1 : 12

2006-09-11 01:19:43 · answer #1 · answered by Brenmore 5 · 0⤊ 0⤋

M/N=13/11
(M-N)/(M+N)=2/24=1/12 (BECAUSE(A^2-B^2)=(A+B)(A-B))

2006-09-11 07:42:31 · answer #2 · answered by sami1989 2 · 0⤊ 0⤋

m^2-n^2 : (m+n)^2= (m+n)*(m-n)/(m+n)^2=(m-n):(m+n)
= 2:24=1:12

2006-09-11 07:28:12 · answer #3 · answered by saby 2 · 0⤊ 0⤋