using digits 2,3,4,5 all at a time how many numbers can be formed?

Question

This question comes under Permutation.

Answer 1

24 if no numbers can be repeated and 256 if they can

Answer 2

Since you have to use all four digits, you can choose any one of the four for the first digit, any one of the three remaining digit for the second digit, any of the two remaining for the third digit, and the fourth digit must be whichever that's not used, resulting in the choices of 4 x 3 x 2 x 1 combinations or 24 possible numbers.

Answer 3

24

Answer 4

basically, there are 4 digits in this problem (2, 3, 4, and 5)

since there are 4 digits....the solution for this is

1 x 2 x 3 x 4 = 24

24 possible combinations..

if there are 5 digits...the solution goes like this...

1 x 2 x 3 x 4 x5 = 120 possible combinations...

Answer 5

16

Answer 6

the numers will be 4 digited no.
now u can fill the first place with any of these fours i.e in 4 way
as soon as u fill the first place the second place can be filled by the remaining three nos in 3 way, thus the second plce in 2 way and last one in 1 way.
so total no of 4 digited numbers can be formed r 4*3*2*1=24

Answer 7

4! = 24

Answer 8

Becaue we have to use all 4 digits to make numbers, we use the formula 4P4 (exact permutation notation is not possible here)

So, 4P4 = 4!/(4-4)! = 4!/0! = 4!/1 = 1x2x3x4 = 24, is the answer

Answer 9

2x 3 x 4 x 5 = 120 combinations

Answer 10

16 numbers

Answer 11

If you have to use all 4 digits once each, you can make 24 numbers.

2345, 2354, 2435, 2453, 2534, 2543
there will be 6 sets of numbers for each different starting number