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4 answers

Because it gives us a reference point upon which we can quantify negative charge. Now, If you have some amount of Coulombs, you can divide by the charge on one electron to see how many units of 'elementary charge' you have.

2006-09-10 19:05:17 · answer #1 · answered by Sean H 2 · 2 0

The Millikan oil drop experiment measures the ratio of an electrons charge to its' mass.

There are a number of physical things that depends on that ratio. An important one?

If that ratio was not very close to what it is stars would not have been formed. So, you wouldnt be asking the question.

2006-09-10 19:12:34 · answer #2 · answered by Bob 7 · 1 0

It is a fundamental fact of nature that a scientist needs to know for any number of reasons. It is sort of like asking why does anyone need to know the value of Pi. It's used for all kind of stuff.

2006-09-10 19:04:06 · answer #3 · answered by s_e_e 4 · 1 0

How about F=qE=mg? and you get to figure out the sign of the charge.

2016-03-27 06:38:36 · answer #4 · answered by Maria 4 · 0 0

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