from 1960-1990 the average annual US consumption of pork dropped according to the linear equation of y= -1/3x + 62 . the average annual cosumption of chicken rose according to the linear model y= 7/6x + 31. for which years did the US consumption of chicken exceed the consumption of pork?
2006-09-10 18:23:22 · 5 answers · asked by sonovabeeech 1 in Science & Mathematics ➔ Mathematics
First, find the crossover point:
pork=chicken
-x/3+62 = 7x/6+31
(solve for x)
31 = 7x/6+2x/6 = 9x/6
31*6/9 = x
20.67 = x
That is, 1960+20 2/3 = 1980 + 2/3 year
Now you need to interpret this. For 1/3 of 1980 and every year after that chicken consumption exceeded port consumption.
To check your answer, it's good to substitute 20.67 into both the pork and the chicken equations to see that you did get the correct crossover.
This is also a good problem to work with a graphing calculator.
2006-09-10 18:40:36 · answer #1 · answered by modulo_function 7 · 0⤊ 0⤋
(-1/3)x + 62 < (7/6)x + 31
Multiply everything by 6
-2x + 372 < 7x + 186
-9x < -186
x > 20 2/3
x > 20 years and 8 months
so answer, During 1980 to 1990 the consumption of chicken exceeded the consumption of pork.
2006-09-11 01:41:12 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
since they are linear relations; u equate y1=y2
get ur x value(assuming ur x is the time with 1960 as reference ie x=0)
after u get the x value add it back to 1960>this is the year wen chicken = pork
the rest needless for me to say anymore...
2006-09-11 01:33:55 · answer #3 · answered by RAWR 1 · 0⤊ 0⤋
1976
2006-09-11 01:28:35 · answer #4 · answered by Sordenhiemer 7 · 0⤊ 0⤋
Hey both 'x' are different?
2006-09-11 01:29:33 · answer #5 · answered by s g 3 · 0⤊ 0⤋