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one long-distance company offers a plan such that each minute costs $.10 and each call has a $.10 service charge. Solve an inequality to find the maximum number of minutes you can talk for $3.00.

2006-09-10 18:12:09 · 5 answers · asked by sonovabeeech 1 in Science & Mathematics Mathematics

5 answers

.10x + .10 <= 3

.10x <= 2.9
x <= 29

ANS : at least 29 minutes for one call will cost you $3.00

2006-09-10 19:11:00 · answer #1 · answered by Sherman81 6 · 0 0

Don't remember much about "solve an inequality," but it sounds like you'd be able to talk for 29 minutes. Or get the plan with no service charge. Or a party line!

2006-09-11 01:15:07 · answer #2 · answered by stringfellow 3 · 1 0

Presumably they want you to set up the inequality too.

Let x be the number of calls you make.
Let y be the number of minutes you talk.

Your cost is going to be ten cents per call, plus ten cents per minute.
Your total cost must be less than or equal to $3.00

Your inequality is 0.1x + 0.1y <= 3

... and yes, the maximum minutes you could talk would be 29, since you must make at least one call in order to have any minutes at all. However, making more than one call would just take away money that you could spend on minutes.

2006-09-11 01:22:38 · answer #3 · answered by Bramblyspam 7 · 1 0

1 call 29 minutes

2006-09-11 01:20:03 · answer #4 · answered by Anonymous · 0 0

maybe I am stupid but 28 mins?

2006-09-11 01:14:59 · answer #5 · answered by leahb1979 2 · 0 0

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