3x - 2y = 12
(a) (-4, ?) (b) (?, -3) This is the problem.
I really need help because I am being tested over this Tuesday and I could not find these kind of problems in the test book.
2006-09-10 17:02:13 · 4 answers · asked by prettygirl7641 1 in Science & Mathematics ➔ Mathematics
In a) you're looking for the y coordinate. Sub -4 into the equation and solve for y.
In b) same thing except you're given the y coordinate, need to find x coordinate.
2006-09-10 17:05:27 · answer #1 · answered by Epicarus 3 · 1⤊ 0⤋
simply plug the number in and solve:
(a)
3(-4) - 2y = 12
-12 - 2y = 12 <-- start solving by isolating y.
-2y = 12 + 12 <-- divide by -2y
y = 24/(-2)
y = -12
so (a) is (-4, -12)
(b)
3x - 2(-3) = 12
3x - -6 = 12 <--negatives cancel
3x + 6 = 12 <--isolate x
3x = 12 - 6
3x = 6
x = 6/3
x = 2
so (b) is (2, -3)
2006-09-11 00:08:57 · answer #2 · answered by Rockstar 6 · 0⤊ 0⤋
a) -12
b) 2
2006-09-11 00:12:02 · answer #3 · answered by Bethany 7 · 0⤊ 0⤋
3x - 2y = 12
-2y = -3x + 12
y = (3/2)x - 6
a.)
y = (3/2)(-4) - 6
y = (-12/2) - 6
y = -6 - 6
y = -6 + (-6)
y = -12
b.)
-3 = (3/2)x - 6
(3/2)x = 3
3x = 6
x = 2
ANS :
a.) -12
b.) 2
2006-09-11 01:59:13 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋