2006-09-10 16:42:09 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
put the 4 90 degree angles in the corners
2006-09-10 16:44:39 · answer #1 · answered by nutz1228 2 · 1⤊ 0⤋
Arrange 4 isoceles right triangles to form the square. The hypotensuses of the triangles are the sides of the square.
2006-09-10 16:57:29 · answer #2 · answered by jinxy 2 · 0⤊ 0⤋
Place the points of the 90 degree angles in the middle of the square so that the shorter sides of each triangle form an x.
2006-09-10 16:47:38 · answer #3 · answered by Twinkle 2 · 0⤊ 0⤋
This is only possible if the four right triangles are all isoceles (the two sides adjacent to the right angle have the same length), and if they are all congruent (identical).
To see how this is done, draw the two diagonals of a square.
2006-09-10 17:08:25 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1. Draw a square.
2. Draw a vertical line bisecting the square.
3. On each of the smaller squares, draw a diagonal line from corner to corner.
2006-09-10 16:47:20 · answer #5 · answered by kent chatham 5 · 1⤊ 0⤋
first draw a square, now draw a line connecting opposite corners.
Those 2 lines from 4 right triangles.
2006-09-10 19:28:25 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
arrange the four right angles with the points in the middle.
2006-09-10 16:46:36 · answer #7 · answered by Anonymous · 1⤊ 0⤋
In the square you traced the equal diagonals
2006-09-10 16:46:11 · answer #8 · answered by mircea h 1 · 0⤊ 0⤋
all points to the middle
2006-09-10 16:45:01 · answer #9 · answered by funlady6632@yahoo.com 6 · 0⤊ 0⤋
put their points together
2006-09-10 16:45:12 · answer #10 · answered by Big hands Big feet 7 · 0⤊ 0⤋