Is the square root sign drawn with a line over it? If so, wherever the line stops tells you which terms are under the square root sign.
If there is no line drawn with the square root, then I would assume you are graphing y = sqrt(x) - 2
2006-09-10 16:29:45
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answer #1
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answered by whatthe 3
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The way you have written y=âx-2, I would say the former, but we can't tell exactly unless we see the original material you are working from. Usually, the radical sign has a top line that extends over all of the elements that are included. So if on your original material, the radical sign includes the -2, then you would graph â(x-2) If it does not, then you graph â(x) - 2.
2006-09-10 23:33:49
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answer #2
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answered by just♪wondering 7
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unfortunately the computer square root sign does not convey the information from your textbook, so you should have enclosed whatever was under to square root sign in parentheses. You should understand that you are taking the square root of whatever is underneath the horizontal line above the term. Hopefully the term would also be enclosed in parentheses. I'd work it out both ways and note you didn't understand the problem so your teacher can look at the intended one.
2006-09-11 00:50:14
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answer #3
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answered by ronw 4
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Can't tell exactly by the question. Are you in the section with horizontal translations? is so, (x-2) ......if vertical translations, try other.
The square root sign is a bit vague.
Also, if the square root sign goes all over x-2 , then it's square root(x-2)
2006-09-10 23:32:16
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answer #4
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answered by Double Century Dude 3
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It would mean the first, square root of x, minus 2. Look up a list of precedence of operators.
2006-09-10 23:28:33
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answer #5
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answered by Ken H 4
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depends, is the sqrt over both the x and -2 or just the x
y = sqrt(x - 2)
for a graph, go to http://www.calculator.com/calcs/GCalc.html
type in sqrt(x - 2), click enter, then type in -sqrt(x - 2)
2006-09-10 23:31:37
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answer #6
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answered by Sherman81 6
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As your teacher not applying bracket, so square-root apply only at x.
2006-09-10 23:50:54
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answer #7
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answered by (^___^) 2
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