Find two consecutive integers such that the sum of 3 times the first integer and 6 times second integer is 24.

Question

Please define the variables you use.

Answer 1

3x + 6y = 24

y = x + 1

3x + 6(x+1) = 24
9x = 18
x = 2

x = 2, y = 3

Answer 2

2 and 3

Answer 3

at first look, it is a question approximately 2 unknown integers, "x" and "y", and if that became into each and all the counsel we had, this question may be plenty harder to sparkling up. in spite of the undeniable fact that, the biggest to understanding this question is the clue that asserts the integers are consecutive. in the event that they're consecutive, it ability that certainly one of the two numbers is one extra beneficial than the different. Or, in different words, that certainly one of our integers is X and the different is "x+a million". Now that all of us comprehend that - the equation is in simple terms this: 2(x) + 4 (x+a million) = 10 2x + 4x + 4 = 10 6x + 4 = 10 6 x = 6 x = a million because of the fact the 1st integer is "x" and the 2d is "x+a million", the answer for x tells us that between the integers is a million (x) and the different is two (x+a million). permit's verify it and notice: 2(a million) + 4(2) = 10 seems good!

Answer 4

Let two consecutive numbers are x and x+1
3x+6(x+1) =24
3x +6x +6 =24
9x = 18
x= 3
Then two numbers are 3 and 4

Answer 5

3x + 6(x + 1) = 24
3x + 6x + 6 = 24
9x + 6 = 24
9x = 18
x = 2

The numbers are 2 and 3

Answer 6

3x + 6(x + 1) = 24
3x + 6x + 6 = 24
9x + 6 = 24
9x = 18
x = 2

The numbers are 2 and 3

Answer 7

2 and 3

I did it in my head cuz I are smart!

3X + 6(X + 1) = 24
3X + 6X + 6 = 24
9X + 6 = 24
9X = 18
X = 2, ( X + 1) = 3

Answer 8

2 and 3. 3X2=6, 6x3=18. 6+18=24.