Is: 2 / x^2 , when differentiated: -4x^-3 ?
I made 2 / x^2 = 2x^-2 , then used the power rule. Is this alright?
Please help a beginning calculus student :(
2006-09-10 13:07:22 · 4 answers · asked by Moosehead 2 in Science & Mathematics ➔ Mathematics
yes that is correct, and your method is correct as well
2006-09-10 13:11:55 · answer #1 · answered by jdrisch 2 · 0⤊ 0⤋
ok. we will do the 2d area first. y=x^6/x^4. you want to divide. once you divide a variable raised to a means with the help of a variable raised to a means, you subtract the exponets. y=x^2 y'=2x the quotient rule- lo de hi-hi de lo throughout lo lo or f*g'-g*f'/f^2 y=x^6/x^4 y'= (x^4)*(6x^5)-(x^6)*(4x^3)/(x^4)^2 y'=6x^9-4x^8/x^8 y'=2x^9/x^8 y'=2x, it is what you get utilising the different technique, that's a lot shorter
2016-11-26 00:15:46 · answer #2 · answered by ? 3 · 0⤊ 0⤋
Quotient Rule
2/(x^2) =
((2)'(x^2) - (2)(x^2)')/((x^2)^2) =
(0(x^2) - 2(2x))/(x^4)
(-4x)/(x^4)
x(-4)/(x^4)
-4/(x^3)
-4/(x^3) is the correct way to put it, but -4x^-3 is also the answer.
2006-09-10 13:48:32 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
Congratulations. This is the best and shortest way.
2006-09-10 13:12:42 · answer #4 · answered by vahucel 6 · 0⤊ 0⤋