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What is (16-5)x[(56/8)-3^2+6]

Is it 4?

2006-09-10 12:23:32 · 16 answers · asked by grasshopperwar2000 1 in Science & Mathematics Mathematics

Sorry, 16-15... I will still give you points for answering the given question.

2006-09-10 12:26:59 · update #1

16 answers

=11x(7-9+6)
=11x4=44

2006-09-10 12:24:48 · answer #1 · answered by Anonymous · 0 1

(16 - 15) x [(56/8) - 3^2 + 6]
= 4

2015-07-16 13:40:12 · answer #2 · answered by Krishnamurthy 7 · 0 0

assuming 3^2 means two is the exponent... (Sorry, I am new here)


(16-5)x[(56/8)-3^2+6]
(16-5) x (7 - 9 + 6)
11 x 4 = 44


*** I just saw your edit -- the answer is then 4. Good job!

2006-09-10 12:29:16 · answer #3 · answered by Shay 1 · 0 0

If its (16-5), its 44. If its (16-15), its 4.

2006-09-10 12:31:12 · answer #4 · answered by Kate T 1 · 0 0

(16-5)x{(56/8)-3^2 +6]= (16-5)X(7-3^2+6)=11x(7-9+6)=11x4=44

2006-09-10 12:33:07 · answer #5 · answered by Anonymous · 0 0

44 if it's (16-5), 4 if it's (16-15).

2006-09-10 12:29:36 · answer #6 · answered by rissaofthesaiyajin 3 · 0 0

I'll break it down....
(16-5)x[7-3^2+6]
(16-5)x[7-3x3+6]
(16-5)x[7-9+6]
(16-5)x[4]
11x4=44

2006-09-10 12:32:24 · answer #7 · answered by Yes Yes 1 · 0 0

Howdy Grasshopper,

If the equation began, 16-15, then yes... the answer is four. (4)

Butch

2006-09-10 12:33:04 · answer #8 · answered by Butch 3 · 0 0

-88

16-5=11
56/8=7
3^2=9
9+6=15
7-15=-8
-8x11=-88

2006-09-10 12:30:18 · answer #9 · answered by AFR1KA 2 · 0 0

yep its 4 if you use 15

2006-09-10 12:30:27 · answer #10 · answered by wing_gundam 3 · 0 0

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