a is not correct on its face: higher energy orbits fill first. But there is a gotcha here: the orbital energy is negative -- a photon is emitted when an electron falls into an orbit, and energy is conserved. So, if we understand that the most negative energy levels fill first, then a can be considered correct.
b is correct.
c is correct. Note that quantum mechanics puts a different spin on this. (Pun unintentional.)
d. is correct.
Hence, e is correct.
2006-09-10 11:03:41
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answer #1
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answered by Anonymous
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In a traditional first year chemistry course where you are learning the chemical properties of elements and compounds, and how they form, all of these statements are correct (e). It's the shell theory, where the max on the first shell is 2, 2nd shell is 8, third shell is 18, and proton count must = electron count for the element to remain stable. We now know that electrons really don't orbit the nucleus as we once thought, but the theory works quite nicely to explain how electrons in the outer shell are shared to make a stable molecule or compound
2006-09-10 11:03:08
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answer #2
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answered by April 6
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d) is not correct
For example, the Cl- anion and the argon gas have both the same number of electrons in their outer orbit, but their properties are clearly different from each other. Argon is a gas at usual conditions, while Cl- anion is not. Cl- has an electric charge, while argon doesn't. These are just some examples of different properties between them.
2006-09-10 11:11:27
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answer #3
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answered by Illusional Self 6
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The answer is "e"
there is mistake on the writing of part b, which is the "greater' the quantum number the higher the energy of the orbit
see this link if you would like to see a picture of Bohr's model, and more in depth explanation.
http://en.wikipedia.org/wiki/Bohr%27s_Model
2006-09-10 11:08:02
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answer #4
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answered by jdrisch 2
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you can say c as electrons do not orbit but occupy a cloud of probable positions which looks like an orbit. but if c is incorrect then e is incorrect. however is any one has to be incorrect, then e is always incorrect so you will have 2 incorrect answers including e so the question itself is wrong
2006-09-10 11:02:08
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answer #5
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answered by firstlennsman 1
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It is a flawed question...
If it were "E" then none of them are wrong. If one of them are wrong then it would be 2 wrong not just 1
2006-09-10 11:02:53
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answer #6
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answered by o_r_y_g_u_n 5
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the answer is e. E is the one that is incorrect
Hope to help
2006-09-10 10:59:18
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answer #7
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answered by kindaworried 1
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search google.com or reference.aol.com they will tell u the answer
2006-09-10 11:02:14
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answer #8
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answered by ? 3
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