3y=6x-9 what is the x-intercept? what is the y-intercept?

Answer 1

Part one;

when you say x-intercept , it means y must be 0 ; y = 0
if y = 0
3y=6x-9;
3*0 = 6x -9;
0 = 6x - 9;
6x = 9;
x = 9/6 ; x = 3/2
( 3/2 , 0 )

Part Two;

when you say y-intercept , it means x must be 0 ; x = 0
3y=6x-9
3y=(6*0)-9
3y = -9 ;
y = -9/3; y = -3
( 0 , -3)

Good Luck.

Answer 2

well let's see...

the y-intercept is when the line crosses the y-axis. The x value must be zero when the line crosses the y-axis, right? So... you just plug in a zero for x in your equation and work the algebra until you can isolate y on one side...

so, you say 3y=6x-9... so if x was zero, what would y be?

3y = 6(0)-9 (substitute zero for x)

3y = 0-9

3y = -9

y = -3 (divide everything by three)

OH! there you go... that's the y-intercept.

To get the x-intercept, you just do the same thing the other way around... plug in a zero for y instead... and then isolate x.

Answer 3

remove a factor of 3 to simplify the problem

y=2x-3. by inspection the y intercept is -3 and the x intercept is given by y=0 so

0=2x-3 giving that 2x=3 so x=1.5

Answer 4

3y=6x-9
y=2x-3
x-intercept: (3/2, 0)
y-intercept: (0, -3)

Answer 5

x-intercept is when y = 0
0 = 6x-9
x = 3/2

y-intercept is when x = 0
3y = -9
y = -3

Answer 6

for y intercept put x=o
so y intercept=-3
for x intercept put y=0
x intercept=3/2

Answer 7

y intercept is -3
xintercept is 3/2
it think this is right

Answer 8

first you solve for y
-> y=2x-3
to find the x-int, set y=0
to find the y-int, set x=0