20.The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.
A) 8 in. B) 9 in. C) 10 in. D) 7 in.
2006-09-10 09:59:35 · 3 answers · asked by BlueEyes4172004 1 in Science & Mathematics ➔ Mathematics
w = width
=> length = 2w + 8
perimeter = 2 x width + 2 x length
=> 64 = 2w + 2(2w+8)
=> 64 = 6w + 16
=> 6w = 48
=> w = 8
2006-09-10 22:32:08 · answer #1 · answered by mitch_online_nl 3 · 0⤊ 0⤋
If the width is x inches, then the length is x + 8. The perimeter is 2x + 2(x + 8) = 4x + 16. So:
4x + 16 = 64
4x = 64 - 16
4x = 48
4x = 48/12
x = 12 in.
2006-09-10 18:36:59 · answer #2 · answered by Dimos F 4 · 0⤊ 1⤋
its A)
the equation is 2x+2(2x+8)=64
2x+2(2x+8)=64
2x+4x+16=64
-16 -16
6x=48
x=8
2006-09-10 17:08:22 · answer #3 · answered by afireinsideme [DF] 6 · 0⤊ 0⤋