a cab of paint will cover 70 square feet. how many cans of paint are to paint a 5 feet high and 98 feet long? help and explain 1.3?
2006-09-10 08:29:39 · 6 answers · asked by katie w 1 in Science & Mathematics ➔ Mathematics
5 feet high and 98 feet long:
area = length * width = 98 * 5 = 490 square feet
a can covers 70 square feet:
490 / 70 = 7
therefore 7 cans are needed.
2006-09-10 08:33:18 · answer #1 · answered by Hex 2 · 0⤊ 0⤋
First calculate the area of the surface you want to paint. This is equal to 5*98=490. Next, divide this by the amount that each can can paint: 490/70=7 cans.
2006-09-10 08:41:16 · answer #2 · answered by bruinfan 7 · 0⤊ 0⤋
ok, this is really easy,
first find out the area so do
98 * 5 and that equals 490 square feet
1 can = 70 square feet
x cans = 490 square feet
from there its proportions
70x = 490
490 divided by 70
equals 7 cans
and there you go!
2006-09-10 08:38:13 · answer #3 · answered by sur2124 4 · 0⤊ 0⤋
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2016-11-07 01:21:35 · answer #4 · answered by ? 4 · 0⤊ 0⤋
5x98=490
490/70=7
you will need 7 cans
Improve your english
2006-09-10 08:33:24 · answer #5 · answered by Farid R 2 · 0⤊ 0⤋
Your question sucks
2006-09-10 08:34:47 · answer #6 · answered by so sick of being broke 2 · 0⤊ 0⤋