Homework help please! Can someone please solve this and SHOW their work. I have the answer by checking the back of the book, but I don't know how it came about. I've been trying to solve this problem for over an hour, but with no luck. Please help. Thanks.
Directions: Factor each polynomial. In some cses, you will need to factor out a constant monomial term.
First problem:
(a+3)(a^2 + 5a) - 6(a+3)
Remember, please show your work! ^_^
Thanks again,
tc9rocks
2006-09-10 08:17:54 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
You're not solving for "a". You have to factor the polynomial, so nothing is necassarily is needed on the other side of the "=" sign.
2006-09-10 08:28:40 · update #1
The answer in the back of the book is:
(a+3)(a-1)(a+6)
2006-09-10 08:30:12 · update #2
oh my god you`re really lame....
(a+3)(a^2+5a)-6(a+3)=(a+3)(a^2+5a-6)=(a+3)(a^2-a+6a-6)=
(a+3)(a(a-1)+6(a-1))=(a+3)(a+6)(a-1)
Please go tell your teacher to teach you this!
2006-09-10 09:20:46 · answer #1 · answered by ioana v 3 · 0⤊ 0⤋
(a+3)(a^2+5a)-6(a+3)...
Edit: (a+3)(a^2+5a) - 6(a+3) becomes [(a+3)(a^2+5a) - (a+3)6]...
BOTH terms contain (a+3).. and you have (a+3)[(a^2+5a)-6]...
first... factor out the common factor in each term... namely (a+3)..
becomes (a+3)(a^2+5a-6)...
now factor (a^2+5a -6) into the form (a?X)(a?Y)
You know that a^2 factors are (a)(a)...
You also know that one of the parts of the terms is positive and one is negative because (+)(-) = (-)...
so just expand these out...
(a + X)(a - Y)... where XY= 6 and X-Y = 5... What fits this?...
for XY you have 1*6, 2*3; for X-Y (and taking from the previous two) you have only 6-1=5...
So you have (a + 6)(a -1)...
now put them back together for (a+3)(a+6)(a-1) and re-arrange into numerical order (I'll let you do that part)
2006-09-10 08:38:11 · answer #2 · answered by ♥Tom♥ 6 · 0⤊ 0⤋
a^3+5a^2+3a^2+15a-6a-18
a^3+8a^2+9a-18
I multiplied the a in the 1st () by everything in the 2nd () and then multiplied the 3 in everything in the 2nd (). -6 was mutliplied to everything in the 3rd (). Then added the a's which were the same power.
2006-09-10 08:25:32 · answer #3 · answered by Mariposa 7 · 0⤊ 0⤋
Unless I'm terribly mistaken, you have not given use the entire equation??? On the assumption that you want to solve for "a",
you must give us something on the other side of an "=" sign. In the information at hand, there is no "other side" of the equation, thus, "a" can be anything!!
2006-09-10 08:27:13 · answer #4 · answered by wizardmenlopark 2 · 0⤊ 0⤋
(a+3)(a^2 + 5a) - 6(a+3)
(a+3)1(a^2 + 5a) - 6(a+3)
a+3+a^2+5a-6a-18
6a-6a+3+a^2
3+a^2
???
2006-09-10 08:27:54 · answer #5 · answered by ilh369 3 · 0⤊ 0⤋
Yes I do know maths my favorites subject. No why should I do it for you? are you prepared to pay me? as the old saying goes"you don't get something for nothing" sorry! your on your own there.
2006-09-10 08:23:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Me-I married a ninja by using fact the voice ordered me too. My mom-I shot a cop by using fact i substitute into in love. My Dad-I kissed a cop by using fact i had to. Older Sister-I sang to my socks by using fact i won't have the ability to administration myself. youthful Sister-I married my puppy rock by using fact i substitute into inebriated. Grandpa-I shot my babysitter by using fact i had to. Grandma-I punched Lebron James by using fact he substitute into bare. Gotta love kinfolk reunions. precise?
2016-09-30 13:24:05 · answer #7 · answered by cosco 4 · 0⤊ 0⤋
=We don't know math so do it yourself
2006-09-10 08:20:05 · answer #8 · answered by Anonymous · 1⤊ 0⤋