hi how would you factor and solve this please explain so i can remember
x(exponent2) + 3x = 0
ps thanks to everyone who answered my last question!
2006-09-10 08:10:23 · 5 answers · asked by katie w 1 in Science & Mathematics ➔ Mathematics
Look for the variable that both terms have in common, which is x, then factor it out.
x^2 + 3x = x * (x + 3) = 0
x = 0
or
x = -3
2006-09-10 08:13:37 · answer #1 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
Do you notice that both the x^2 and the 3x have an x in them?
This means that "x" is a common factor to both terms (this means that you can divide "x" evenly into both terms)
So, we "factor" out an x
So, x^2 + 3x = 0
becomes x(x + 3) = 0
You might wonder where the "x + 3" comes from
When I take x^2 and divide it by "x", I am left with x
When I take 3x and divide it by "x", I am left with 3.
So, when I divide x out of "x^2 + 3", I am left with "x + 3"
Anyway, now we have to actually solve for x.
We have the equation x(x+3) = 0
This means that either x = 0, OR x + 3 = 0
For the second bit (x + 3 = 0), this can only be solved by the value -3.
So, the two solutions are
x = 0 or x = -3
2006-09-10 15:32:30 · answer #2 · answered by whatthe 3 · 0⤊ 0⤋
x^2+3x=0 the only thing in common to both is an x.... factor out the x an you have... x(x+3)=0 From here you can have two solutions that make this true.... x=0 and x= -3.
2006-09-10 15:15:38 · answer #3 · answered by who be boo? 5 · 0⤊ 0⤋
ok this is the easiest type.
x^2 +3x =0
Now x is in both of the numbers so factor it out.
x( x +3)
and there you go, it's factored
2006-09-10 15:13:46 · answer #4 · answered by sur2124 4 · 0⤊ 0⤋
x^2+3x=0
x^2=-3x
therefore, -3=(x^2)/x
which mean x=-3
or
x(x+3)=0
which means x=0
Therefore, x=3, x= 0
:)
2006-09-10 15:13:41 · answer #5 · answered by Mr. Riz 6 · 0⤊ 0⤋