what's the emperical formula for a compound with 52% C , 13% H, and 35% O?

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what's the emperical formula for a compound with 52% C , 13% H, and 35% O?

if possible please show the way how u got the answer & thanx a lot

2006-09-10 07:31:40 · 2 answers · asked by ramzinammour 2 in Science & Mathematics ➔ Chemistry

2 answers

assume MW is 100g/mol

52% C= 52 grams
52g/12g/mole=4.3 moles

13% H= 13 grams
13g/1.01g/mole=12.8 moles

35%O= 35 grams
35g/16.00g/mole=2.2

empirical formula C4H13O2

2006-09-10 08:00:26 · answer #1 · answered by Natasha B 4 · 0⤊ 0⤋

Just remember the numbers she divides by are the molecular weights of the element. Carbon is about 12, Hydrogen 1 and so on and so on...

2006-09-10 17:19:00 · answer #2 · answered by angeliquedesjardins 3 · 0⤊ 0⤋