Suppose the y-values increases and the x-values increases How would this show on a table and on a graph?

Answer 1

If they increase at the same rate, it would appear as a straight diagonal line. If they increase in different increments it will be mor of a stair step affect.

Answer 2

I'm not sure what graph you are starting with but graphically your line would move up to take care of the y-values increasing, and the line would move the right to take care of the x-values increasing. On a table the x and y values would just get larger.

Hope this helps.

Answer 3

ok so surely graph all the standards with the time (days) on the horizontal axis and the passengers on the vertical axis. you'll discover the graph has the first area being of a particular steepness, (from 10 to 20 there is an develop of three hundred) yet then on the subsequent ones there is an develop of six hundred for each. for this reason the airfare change is on day 20 because up till that aspect it higher with the help of three hundred and then six hundred on every time phase from then on (im assuming airfare were given more interior of your means, yet thats besides the point ). you've a graph of two line segments, one going from 10 to 20 (of a particular steepness it is 'upward push over run' (three hundred/20-10) = 30, the subsequent ones may have a gradient of 60. On day 25? .. approximating a linear equation (a instantly line between each aspect) it will be an develop of three hundred from day 20, it is 1300+three hundred = 1600. even as will it exceed 3500? approximate the line contained in the form y = mx + c the position 'm' is the gradient of a instantly line phase (in our case its 60 for this 2d steeper line). (the position x = no of days and y = passengers) for this reason y = 60x + c 'c' is largely the y intercept of that, so even as x = 0, what does y want to be to get the right values? we are able to install a cost all of us know (i.e. x = 30, y = 1900) for this reason 1900 = 60(30) +c supplies us 1900 = 1800 + c , meaning 'c' for our steeper line is one hundred y = 60x + one hundred even as will passengers bypass above 3500? 3500 = 60(x) +one hundred means 3400/60 = x , giving x = fifty six.6666 ... for this reason 2 thirds the way by the 57th day it truly is going to attain a cost of 3500 , so with the help of the authentic of fifty seven days, it would want to have exceeded 3500. so some distance because the 2750, similar ingredient y = 60x+one hundred 2750 = 60(x) +one hundred 2650/60 = x meaning x = 40 4.166 so on which day does it 'about' have 2750? .. on the authentic of 40 4 days it has basically about that. having said that, it would want to be evaluated utilising the graph for an approximation, the position you basically draw horizontal and vertical traces on the standards of interest, and word the position they more desirable or less are. sturdy success.

Answer 4

If the x and y values increase uniformly,
on a table it would be represented by values
in a graph, it would be represented by a straight slope

Answer 5

if your y increases and at the same time your x increases, you will have a diagonal line going up and right.

Answer 6

It would show up on a table reading:Do your own homework

Answer 7

up and right.....if y inc faster than x.....up more than right.....if y inc faster than y......right more than up.....but both in that direction