what are the units you messure area in ????

Answer 1

square meter, square kilometer, square hectometer, square dekameter, square decimeter, square centimeter, square millimeter, square micrometer, square nanometer, hectare, are, barn, square mile, square yard, square foot, square inch, circular inch, township, section, acre, rood, square chain, square rod, square perch, square pole, sabin, arpent, cuerda, plaza, election cross section

Answer 2

You can measure area with linear units in a squared notation: like square yards, square meters, square miles etc.
There are also some units that designate area measures:
like an acre or alqueire which are used to refer to land area.

Answer 3

the desirable line we could opt to bypass for the time of the better right corner of the sq.. the base line we could opt to bypass for the time of the decrease left corner. ytop = mx + d(a million+m^2)^(a million/2) (the place d is the 0.8) ytop(a million) = m + d(a million + m^2)^(a million/2) = a million m of activity is 0.1862436 This makes ytop = 0.1862436x + 0.813756397 ybottom = mx the section is int (x=0..a million, y=ybot.. ytop, dydx) = int(bdx) = b = 0.813756397 = Amax this is exciting this is the comparable fee as difficult yet from an extremely distinctive path. that may no longer Amax? So the optimal section lies someplace for the time of the rotation from this answer to difficult's, eh? Going around the diagonal will leave 2 triangles at each corner, you may even have section a million/2?xbot?ybot and the different could have section a million/2?xtop?ytop. ?xbot = a million + b/m (assume effective slope, unfavorable intercept) ?ybot = m + b ?xtop = [a million -d(a million + m^2)^(a million/2) - b]/m ?ytop = [a million -d(a million + m^2)^(a million/2) - b] leaving us to decrease: m + 2b + b^2/m + [a million -d(a million + m^2)^(a million/2) - b]^2/m for which d/db = 0 supplies: b = (a million -d(a million+m^2)^(a million/2) -m)/2 a million - b^2/m^2 + [a million -d(a million + m^2)^(a million/2) - b](-2nd(a million + m^2)^(-a million/2) - a million/m^2) = 0 Now fixing for b and m will provide us our parallel strains, the minimum element of the triangles, and Amax = a million - Amin a million - (a million -d(a million+m^2)^(a million/2) -m)^2/(4m^2) + [a million/2 -d(a million + m^2)^(a million/2)/2 +m/2](-2nd(a million + m^2)^(-a million/2) - a million/m^2) = 0 you ought to purpose and remedy that for m, yet i could propose finding on the respond below mine relatively.

Answer 4

Area would be square metres, or a variation- square cm or whatever. Length is metres, and volume is metres cubed, or more usually for liquids, litres. Be careful about saying metre square and square metre- a 2 metre square would have lengths of 2 metre, and area of 4 square metre. It's written as m with a superscript 2.

Answer 5

You can use any units you want, cm squared, meter squared, acres, square miles and elephants. As long as you state the unit you are using after the appropiate number, and there is a comparison available

i.e. v cm squared = w mtr squared = x acres = y square miles = z elephants

Hope this helps.

Answer 6

Depends on what area you're measuring. Units of measure that can be used in specific areas are meters (and its smaller units such as centimeters, millimeters, decimeters, etc), feet (inches), hectares, acres, etc...

Answer 7

In the USA, we use square yards, acres, and sections [square miles]

The part of the world on the metric system uses square meters and hectares.

Answer 8

i am not sure what u r measuring. So lets say if you r measuring in ft, area will be squared feet or ft^2. the same for other units.

Answer 9

any measurement of length squared. e.g. millimetre squared, light year squared etc. really doesn't matter what the unit of length is.
also, acres, hectares etc.

Answer 10

For land it's usually acres and hectares