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Do i lose if the cueball hits the 8, but also sinks one of the opponent's ball? The 8 and the cueball still remain on the table.

2006-09-09 02:35:19 · 13 answers · asked by Haopei 2 in Sports Snooker & Pool

13 answers

This is actually a legal shot. Since you contacted the 8 ball first, you have not committed a foul. Your turn simply ends with balls in position. Incidentally, the term "scratch" comes from back in the day when people kept score using chalkboards and when someone committed a foul, they would "scratch" one point off of their total score. So the word refers to any type of foul, not simply pocketing the cue ball. However, if you foul while shooting for the 8 ball, it is not loss of game if the 8 ball remains on the table, your opponent gets cue ball in hand. M.D.-BCA Instructor/Referee.

P.S. Mickey Mantle makes a very good suggestion. He has a good understanding of safety play and using intentional fouls.

2006-09-09 04:03:41 · answer #1 · answered by straight_shooter526 6 · 0 0

It is never, ever, ever a foul to pocket your opponents ball on an otherwise legal shot. If you made a legal shot (hit the 8 first) and pocketed it in the called pocket, you win. It doesn't matter if you the cue ball flew around the table and made 5 of your opponents balls, you still win.

2016-03-27 03:56:52 · answer #2 · answered by Anonymous · 0 0

The easiest way to remember is if you scratch during at the last ball then you lost the game. since you just lost your turn by pocketing your opponent's ball and missing the 8 ball, (no free ball on your opponent's next shot). Then you still in the game.

2006-09-09 02:39:44 · answer #3 · answered by Onny 3 · 1 0

No you don't....assuming you hit the 8 first his turn is next from where the cue ball ended....not a ball in hand foul......might be a situation where you might want to sink his intentionally......lets say that you don't have any shot on the eight and neither does he....for example the 8 is lockup with one of his balls...and he might have one other ball left.....you might on purpose want to sink his ball giving him ball in hand so he and not you have to break out the 8 ball......but remember what goes around comes around and he might just give it back to you for a good defensive shot and then you back to him just looking for him to make some error.....if at the start of this suggestion you had just "whacked" at the 8 ball with no real pocket to go to....you would probably be racking....at least this way you might get lucky and he be the one "whacking" at his ball......good luck on the tour!! send me my 1%!!

2006-09-09 08:16:15 · answer #4 · answered by Mickey Mantle 5 · 1 0

The opponent's ball stays pocketed but you do NOT lose the game. However, it is now your opponent's turn.

2006-09-09 02:40:33 · answer #5 · answered by spindoccc 4 · 1 0

No u just lose a chance but if it his last ball then u may lose because he will get 2 chances

2006-09-10 09:41:41 · answer #6 · answered by Anonymous · 0 1

No u ll not loose the game u just suuferd a foul.
Best of Luck

2006-09-10 19:09:41 · answer #7 · answered by shani s 1 · 0 1

in English pool , if you foul on the black you lose the game .... i don't know the rules to American version

2006-09-09 02:37:51 · answer #8 · answered by Gandalf 3 · 0 0

no, you just lose your turn. it's not a scratch as taylor g said. if you had scratched you would have lost

2006-09-09 02:46:59 · answer #9 · answered by Anonymous · 0 0

no.it is your opponent's turn to shoot.

2006-09-09 02:41:53 · answer #10 · answered by Anonymous · 1 0

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