2006-09-06 04:58:34 · 3 answers · asked by Nema R 1 in Science & Mathematics ➔ Engineering
The bore is the diameter of the hole in the barrel through which the bullet travels. It may be expressed as a fraction of an inch, such as .22, .308, .50 caliber, etc., or in metric units such as 9 mm, 7.62 mm, or in terms of the weight of the lead sphere which would fill the barrel: a 20-gauge shotgun has a barrel that would take a 1/20 pound lead ball. Shotgun barrels are sometimes expressed in inches: .410 for example.
2006-09-06 05:08:05 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The above answer answered the question quite well, but let me add that the numbers can be somewhat deceptive. For instance .22 is USUALLY .224-not always, .22 Savage Hi Power is .227, and there's a few .222's and .223's (however .222 Remington .222 Rem Mag and .223 Remington and .223 WSSM are all .224). Also .280 is really .284, .260 is .264, .25-06 and .250 Savage, .25-35 and 25-20 are .257, .30-06, .300Win Mag .300 WSM, .300 RUM, .308, and most other .30 calibers are .308, but .303 british is .311 and 7.62x39 and 7.62x54 are .312. .38 special is really .357. .40 and .45 caliber gets even worse. When you get into obsolete cartridges you get into even more funky stuff. It goes on and on and on, it can get really confusing, but you just sorta learn it after awhile.
2006-09-06 12:46:08 · answer #2 · answered by Conrad 3 · 0⤊ 0⤋
Hi. 22/100 of an inch.
2006-09-06 12:00:48 · answer #3 · answered by Cirric 7 · 0⤊ 0⤋