I've seen trick shot artists like Mike Massey make all 15 balls in one shot. It's a set-up shot called the dream shot. It still takes a certain degree of skill to pull it off. If you're referring to 15 balls on a break shot, I haven't been able to find many records online, although I can't imagine the record being more than 9 or 10. I'm going to try and find some definite answers and get back to you. I've seen Alex Pagalayan sink 7 balls on a 9 ball rack...and then go on to lose the game. This actually prompts me to want to do some research on pool and billiards records. M.D.-BCA Instructor/Referee.
2006-09-06 06:13:22
·
answer #1
·
answered by straight_shooter526 6
·
0⤊
0⤋
It has to possible. I know that if God decided to be human just long enough to make that shot, he could and would do it, without any sort of minipulation of the laws of physics. Eventhough it is clearly evident in l96vette's link that the chances for a human to pull this off would be STAGGERING, I still think it's technically possible. Needless it wouldn't happen in my lifetime.
2006-09-08 01:08:08
·
answer #2
·
answered by supershadowsniper 2
·
0⤊
0⤋
Me winning the IPT world tour is easier than anybody making all the balls in one shot.
2006-09-06 17:49:14
·
answer #3
·
answered by tyrone b 6
·
0⤊
0⤋
it is possible but you have to arrange the balls, not stacking it in a standard way and yes it should be a trick shot not a regular game
2006-09-06 22:57:37
·
answer #4
·
answered by vener a 2
·
0⤊
0⤋
On a break, the answer is zero. See the link below for a scientific analysis.
2006-09-06 08:07:09
·
answer #5
·
answered by L96vette 5
·
0⤊
0⤋
Yes, if you playing 1-ball.
2006-09-06 07:42:37
·
answer #6
·
answered by smitty 7
·
0⤊
1⤋
On a break or in a trickshot?
2006-09-06 18:54:05
·
answer #7
·
answered by Sk8Boardude27 1
·
0⤊
1⤋
10% its so hard for my opineon but still not impossible
2006-09-06 06:48:27
·
answer #8
·
answered by kewl 2
·
0⤊
1⤋
8% i'm thinking
2006-09-07 21:50:06
·
answer #9
·
answered by Aliza 2
·
0⤊
0⤋
none
2006-09-06 06:49:01
·
answer #10
·
answered by toughasmince 2
·
0⤊
0⤋