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Let A be the event that a student is enrolled in an accounting course, and let S be the event that a student is enrolled in a statistics course. It is known that 30% of all students are enrolled in an accounting course and 40% of all students are enrolled in statistics. Included in these numbers are 15% who are enrolled in both statistics and accounting. A student is randomly selected, and it is found that the student is enrolled in accounting. What is the probability that this student is also enrolled in statistics?

2006-08-28 22:09:59 · 6 answers · asked by Anonymous in Education & Reference Home Schooling

6 answers

answer: 50%

see diagram: (works best in a monospaced font)
-1-2-3-4-5-6-7-8-9-0 (each char represents 5%)
xxxxxx-------------- acct students (30%)
---xxxxxxxx--------- stat students (40%)
(15% overlap)

2006-08-28 22:17:23 · answer #1 · answered by TrickMeNicely 4 · 0 0

50%--half of all students in accounting (30%) are also in statistics (15%).

2006-08-28 22:20:48 · answer #2 · answered by Goddess of Grammar 7 · 0 0

Boil it right down to: (# scholars taking something as well S/E/F) = x = entire enrolled - (# scholars in S/E/F). to remedy, you ought to favor to entice close 2 of the three values. the most important difficulty is to not double count number bodies, that's the position the Venn diagrams are sensible. Even devoid of them, we are able to carry out the accounting with correction as follows: For ease, we are able to carry out all corrections to the bigger/greatest crew even as necessary. We the ideal decision with the intention to in simple terms finally end up treating unique scholars. S 31 - 5 (S/F) - 3 (S/E/F) = 23 E fifty 9 -10 (S/E) - 8 (E/F) - 3(S/E/F) =38 F 15 Summing yields seventy six unique scholars taking a minimum of between the three ...in view that seventy six% are taking between the three, the the relax is our wanted answer, 24%. For the Venn diagram, draw 3 earrings equivalent to the Olympic earrings type ensuring all 3 overlap in the middle (a twin of the first image of source #2). you'll see the 4 overlapping areas the above calc adjusts for. For readability, (31+15+fifty 2) "inflates" the linked fee for the three matters, because of overlap, the position some scholars ought to count number number two times or three times. that's sensible to apply a really decreased get mutually. in case you had entire of 5 human beings to contemplate, in case you knew 2 human beings wore glasses and a pair of were bald, what percentage are neither bald nor positioned on glasses? nicely, it relies upon if any of the bald human beings positioned on glasses, excellent? If no bald human beings positioned on glasses, then in simple terms a million man or woman is neither bald nor wears glasses. If a million bald man or woman wears glasses, then 2 human beings are neither bald nor positioned on glasses. If 2 each body is both bald and positioned on glasses, then 2 human beings are neither bald nor positioned on glasses...

2016-11-23 12:35:08 · answer #3 · answered by Anonymous · 0 0

What is the probability of you putting this in the wrong group?

100%!

;)

You really ought to post these in the Homework Help section. They have nothing to do with homeschooling.

2006-08-29 01:14:27 · answer #4 · answered by glurpy 7 · 0 0

Need to know how many students? If not then way to complicated for me.

2006-08-28 22:15:25 · answer #5 · answered by Anonymous · 0 0

i dont know .......but all i know is you are helping me this semester with statistics

2006-08-29 00:44:51 · answer #6 · answered by Pamela 2 · 0 0

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