1000 lb at 45degrees lattitude would weigh how much more if the earth wasa not spinning???
2006-08-27 18:20:32 · 9 answers · asked by specal k 5 in Science & Mathematics ➔ Engineering
are you saying that centifical force does not act on us???
2006-08-27 18:30:14 · update #1
if i had a metal disk with a magnet on the egde of it spining faster and faster would not make it eventaly fly off???(over come its attration)
2006-08-27 18:33:10 · update #2
Equilateral Radius (a) = 6378.135 km
Polar Radius (b) = 6356.750 km
L=Pi/4 (45 degree)
Radius at a given geometric latitude = (a*b)/ [a^2-(a^2-b^2)*(cos(l))^2]^.5
Radius= 6358.2551 km (at 45 degree)
When we stand at 45-degree latitude, we round on a smaller circle around the axis of rotation of Earth. The Radius is product of radius of earth at given latitude and the Cosine of the latitude:
R= 6358.2551 * Cos (pi/4) = 4495.9653 km
Earth completes one rotation every 24 hours so:
Omega (Angular rotation of Earth) = (2*pi)/ (24*60*60) = 0.0000727 (radian per second)
The centrifugal acceleration resulted from rotation of earth is:
A= R*Omega^2
A= 0.02378
The direction of A is parallel to equilateral plane but only the normal part of it affects our weight. Since we are talking about 45-degree latitude, we have to multiply A by Cos(pi/4) to get the normal component of A (perpendicular to the surface of earth):
Outward acceleration resulted from rotation of earth= 0.01681 (meter per square second).
The gravitational acceleration on earth is 9.86 (meter per square second) at sea level, if the earth didn't spin, then it would be 9.87681 (meter per square second)
So if earth didn't spin, every mass would be 0.17% heavier!
2006-08-27 21:14:32 · answer #1 · answered by Farshad 2 · 0⤊ 0⤋
Mr. Issac Newton's theory of Apple Dropping to the floor can explain well.
F = mg
Weight is Force
Mass is m and always there
Gravity is g and can be varried if in according to your anser
1. If the Eart is not rotate, g will become 0 and F = 0 but mass is always there.
2. So long as the earth rotating at N rev/sec, the centrifigul force is acting and hence g will no longer be 0
I hope this is the answer if memory doesn't fails me
2006-08-28 02:45:49 · answer #2 · answered by Mr. Logic 3 · 0⤊ 0⤋
Most of the previous answers are wrong. We would weigh slightly less due to the absence of the centripetal force. I don't remember the equations to figure that stuff out any more though. Sorry I can't answer your question.
2006-08-28 01:58:42 · answer #3 · answered by Ken H 4 · 0⤊ 0⤋
Centripetal force does have an effect on your weight, but we are so small in comparison to the forces involved that the effect is negligible.
2006-08-28 01:32:49 · answer #4 · answered by nighthawk8713 3 · 0⤊ 0⤋
The rotation of the earth has nothing to do with its weight.
2006-08-28 01:25:02 · answer #5 · answered by obaboman 1 · 0⤊ 0⤋
It wouldn't weigh more, it would weigh less. The earths rotation is what produces the gravity holding us down. No rotation, no gravity, no weight.
2006-08-28 01:28:36 · answer #6 · answered by Lonnie P 7 · 0⤊ 1⤋
this kind of question is generally mistaken. if the earth was not spining , everything generally wild change nad you have another condition.
2006-08-28 03:54:51 · answer #7 · answered by eshaghi_2006 3 · 0⤊ 0⤋
The rotation of the earth has nothing to do with weight. 1000lb would weight 1000lb.
2006-08-28 01:28:43 · answer #8 · answered by cman 3 · 0⤊ 0⤋
Wouldn't matter. You'd be off in space somewhere and would be weightless AND DEAD.
2006-08-28 01:27:03 · answer #9 · answered by john_mason4438 3 · 0⤊ 0⤋