need formula for figuring liquid in piping?

Answer 1

for straight segments of pipe or tubing, use the internal radius (half the internal diameter), multiply by pi (approximately 3.141592654), and multiply that by the length of the pipe. For instance:

Pipe sizes are expressed using the nominal internal diameter, so a segment of 1/2-inch pipe has a nominal inside diameter of 0.5 inch, which translates to a radius of 0.25 inch. HOWEVER, this is only a nominal figure:

A typical Schedule 10 "1/2-inch" pipe has an outer diameter of 0.840 inch and a 0.083-inch wall thickness -- which means the internal diameter is 0.674 inch. This translates to roughly 42.815 cubic inches per 120-inch-long (10 feet) section of uninterrupted pipe.

In Schedule 40, the outer diameter remains the same and the wall thickness is increased to 0.109 inch, which means the internal diameter is 0.622 inch. This translates to roughly 36.463 cubic inches per 120-inch-long (10 feet) section of uninterrupted pipe.

In Schedule 80, the outer diameter remains the same and the wall thickness is increased to 0.147 inch, which means the internal diameter is 0.546 inch. This translates to roughly 28.097 cubic inches per 120-inch-long (10 feet) section of uninterrupted pipe.

Add to that manufacturing tolerances, and if you're dealing with a significant length of pipe, you'll need to measure your stock to make calculations that will give you a reasonably accurate estimate of actual volume.

For elbows and street Ls, and for other "uniform" curves, you can calculate internal volume using the following formula:

Where V is the volume, and
where R is the radius of the curve measured to the center of the pipe, and
where r is the internal radius of the pipe, and
where x is the symbol for multiplication and
where / is the symbol for division and
where D is the number of degrees that the curve makes (a street L is 90 degrees; a complete circle is 360 degrees):

V = 2 x pi x pi x R x r x r x D / 360

Since I can't use exponents in this forum, I didn't use the "squared" symbol. The formula can be expressed a bit simpler like this:

V = 19.7382088 x R x r x r x D / 360

Imagine you're calculating the volume of a 10-ft straight section of 10-inch Sch 80 pipe, having at one end a street L and at the other end a 30-degree elbow:

The straight section has an outer diameter of 10.75 inches and a wall thickness of 0.594 inch, which translates to an internal diameter of 9.562 inches. The internal volume is 8,617.25 cubic inches. Since there are exactly 231 cubic inches in each US gallon, this translates to 26.85 US gallons.

I don't have exemplars of the bends, but let's assume R = 16 for the elbow, and that the other dimensions don't change. That gives us a volume of 601.6 cubic inches for the elbow (about 1.87 US gallons).

Let's assume that R = 30 for the street L, and that the other dimensions don't change. That gives us a volume of 3,383.99 cubic inches for the street L (about 10.54 US gallons).

Together, the internal volume is just over 12,602.83 cubic inches, or 54.56 US gallons.

The foregoing is for simple shapes and only yields static volume. For dynamic fluids, see http://en.wikipedia.org/wiki/Bernoulli%27s_equation

Answer 2

There is no formula lar. Only experiment can tell tell and determine the Desity of the liquid. And hence from there, you may look at the standard LIQUID Density table to get to know the liquid.

Answer 3

Use diameter of pipe to find cross sectional area. Multiply area by length to find volume. If measured in millimeters, the result will be ml or cc.

Answer 4

You were not very specific about what you want to calculate.
I give you a link to the Bernoulli equation. It is used to calculate the velocity and the pressure of a liquid in pipes.

The first example on the page is the one for pipes.
http://www.princeton.edu/~asmits/Bicycle_web/Bernoulli.html

Answer 5

pi x internal radius squared x length of section of pipe in question.