In a room are 2 couples: 2 men(A & B) and 2 women (X & Y). In all they totally have only 2 condoms. One of them has the AIDS and they dont know who it is! Now the question is how does A have sex with both X & Y and B also have sex with X & Y using only the 2 condoms but make sure that none are infected? Meaning the body fluid of none touches the other? This is a tough one with a very logical answer..
2006-08-27 00:10:35 · 24 answers · asked by Anonymous in Entertainment & Music ➔ Jokes & Riddles
If A sticks his d i c k into B, then B sticks his d i c k into X while X has her finger in Y, then everyone is having sex and no one gets infected.
2006-08-27 00:19:31 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Do it like this:
1.A wears the both condom-1 and condom-2 together and sexes X,
2.A removes condom-2 and gives it to B. (the inside of condom-2 is untouched)
3. B has sex with X (since it was condom-2 used by A with X in the first place).
4.A has sex with Y using condom-1 and removes it and gives it to B
5.B puts it on his condom-1 and sexes Y. (condom-1 was used with Y).
This way they all 4 are satisfied & also you are.
Now just tell me, which one are u A,B,X or Y
Anyways thanx for such a good riddle.
2006-08-27 20:41:53 · answer #2 · answered by Ashish B 4 · 0⤊ 0⤋
I figured out the answer:
A wears the both condom-1 and condom-2 together and sexes X,
A removes condom-2 and gives it to B. (the inside of condom-2 is untouched) and B has sex with X (since it was condom-2 used by A with X in the first place).
A has sex with Y using condom-1 and removes it and gives it to B who puts it on his condom-1 and sexes Y. (condom-1 was used with Y). So none of the body fluid touches the other!!!
Boy O boy, That was a tough tough ONE!
2006-08-27 00:39:33 · answer #3 · answered by Kishor K 2 · 1⤊ 1⤋
42
2006-08-27 00:14:16 · answer #4 · answered by http://hogshead.pokerknave.com/ 6 · 1⤊ 0⤋
The men reuse the condoms, and don't take them off after their first intercourse. I hope they're tough condoms!
Edit: Pretty hilarious that some people think you can turn condoms inside out and reuse them.
2006-08-27 00:14:31 · answer #5 · answered by Obeast 2 · 0⤊ 1⤋
logically I would say to you to stop having perverted multipartnered fantasies . okay? this is not funny, nor is it a good riddle, this is not a subject many people find it easy to joke about. aids kills you friend, it is not a joking matter. sorry but it is just not something I could try to figure out except to say the one with aids should abstain period. no sex ever again for anyone with aids. it is too risky to someone elses life.
2006-08-27 00:17:17 · answer #6 · answered by Anonymous · 0⤊ 1⤋
A wears the first condom and have sex with X and then turns it so that the inward side is now the outward and vice-versa and then have sex with Y and the same B does
2006-08-27 00:16:48 · answer #7 · answered by Anonymous · 1⤊ 2⤋
"A" using condom "1" has sex with "X" he doesn’t discharge, withdraws but leaves the condom (Dry on the inside) in "X"
"B" using condom "2" has sex with "Y" likewise doesn’t discharge, withdraws leaving the condom (Dry on the inside) in "Y"
Now "A" using condom "2" has sex with "Y" and "B" using condom "1" has sex with "X" This time the guys can discharge.
QED
2006-08-27 10:33:36 · answer #8 · answered by the Tramp 6 · 0⤊ 1⤋
when a is with x & y he simply wears the same condom
and the same is true for b
they never take them off
2006-08-27 00:14:47 · answer #9 · answered by Nicki's guy 2 · 0⤊ 1⤋
One of the BTech guys at IIT asked me this. Here's the answer,
1. A wears condom 1 and on top of 1 he wears 2.
2. A has sex with X. Inside of 1 contaminated with A, Outside of 2 contaminated with X.
3. A pulls out 1. Inside of 1 is contaminated with A, outside of 1 is still pure. A uses this condom to have sex with Y. Now, inside of 1 is contaminated with A, outside of 1 is contaminated with Y, inside of 2 is pure, outside of 2 is contaminated with X.
4. Inside of 2 is pure. B wears it. Outside of 2 is contaminated with X, so it can be used with X. B has sex with X.
5. Inside of 2 is contaminated with B. Outside of 2 is contaminated with X. B wears 1 on top of 2. Outside of 1 is contaminated with Y. So B can have sex with Y with that condom.
Here's the algorithm simplified.
A wears 1 then 2. Has sex with X. Takes off 2. Has sex with Y. B wears 2, has sex with X. Puts on 1 on top of it, has sex with Y.
Another way to look at the problem is to figure out which condom is contaminated with whom on which side. For males, you just have to see the inside of the condoms. For females, just see the outside of the condoms. Contaminate outside of 2 with X. Let it stay with X. Contaminate outside of 1 with Y. Let it stay with Y. Contaminate inside of 1 with A, let A use it on both females. Contaminate inside of 2 with B, let B use it on both females.
2006-08-27 05:45:24 · answer #10 · answered by pranesh81 3 · 1⤊ 0⤋