No.
If your load is inductive, the capacitor helps bring voltage and current in phase, which in turn improves your power factor.
Remember, resistive loads use energy, but (ideal) inductive and capacitive loads return all their energy to the circuit.
2006-09-02 20:01:35
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answer #1
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answered by margo345 2
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Not all of the time. What kind of capacitor. Is this high voltage or low voltage on a circuit board?
Usually I use capictors ot create a specific frequency, such as a radio frequency or just an amplifier.
For higher voltages, I use capacitors as the primary factor for reducing the 60HZ humming, that is, in equipment. A pre-filter before using electronics to do the rest of the filtering.
Finally, on motors, you'll need the capacitor to start the motor, or even create a "third phase" if needed, this is a load, but the actual working of this is not clear to me.
2006-08-26 17:22:21
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answer #2
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answered by Anonymous
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Yes it draws power from the source until charged and stores it but it does not use power. consider it as a rechargeable battery that draws power while charging and gives it back during discharge.
What also may help clear this up for you is the fact that it draws current that is leading voltage as you have mentioned in your question. When there is 90 degrees between voltage and current the load is purely reactive and consumes no power (watts). Power factor is zero in this condition as compared to 1 when the load is purely resistive.
Watts = Voltage X Current X Power factor.
2006-08-27 04:44:22
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answer #3
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answered by Buffertest 3
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No. In fact, the point of doing so is to reduce energy consumption by improving the power factor. If a load has a power factor much less than one, the circulating current exceeds the useful current and causes additional resistive losses.
2006-08-26 17:23:45
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answer #4
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answered by Anonymous
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Yes if it is a ideal capacitor(pure capacitor having no resistance &No losses) it will not consume the energy. in practical all the capacitor will consume energy . But adding capacitor to asustem will improve the Power factor,so reactive lose will be reduced.
2006-09-02 00:37:49
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answer #5
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answered by Anonymous
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Nope. A capacitor connected across a load feeds back as much power in each half-cycle as it absorbed in the previous one. In mathematical terms, it behaves like an imaginary resistance. All it does is smooth out the voltage.
2006-08-26 21:28:09
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answer #6
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answered by zee_prime 6
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Yes, it is a resistance and thus a load, but it also stores energy so that in the final balance the liberated energy is greater than the energy it consumes. If depending on the model being analyzed the result is equal or less, then it is better not to have it.
2006-08-26 17:25:34
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answer #7
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answered by Alex S 3
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Not exactly as capacitor stores energy. It may take up load and consume but it also stores energy and gives it off to the circuit.
2006-09-01 14:11:29
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answer #8
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answered by sunkenme 1
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