2006-08-26 14:58:22 · 4 answers · asked by harleysug@sbcglobal.net 1 in Consumer Electronics ➔ Other - Electronics
Very few devices will work properly with the type of voltage "regulation" (multiple dropping resistors) described in the first post.
One easy way to regulate this for a low-current application is to use a 3V zener diode and a dropping resistor. Or for currents up to 100mA you could use a National LP2950ACZ-3.0 3-terminal regulator or equivalent. And for higher currents you could use a Rohm BA03CC0T 3-terminal regulator or equivalent up to about 1 amp.
But before you can choose a proper solution for this, both the maximum and typical current draws for the device under power should be known. What are you trying to power?
WK
2006-08-26 15:55:33 · answer #1 · answered by olin1963 6 · 0⤊ 0⤋
You will need 4 Resistors of the same size Ohms capable of handling the current. You wire and solder them together in series. One after the other. This will give you 4 voltage drops of 3, 6, 9 and 12 volts. I will try to draw a picture. This best I can get it.
..- Battery +...wire... Resistor ... Resistor ... Resistor. . Resistor
----------------------------------......3 v------I------6 v---------9 v-----12 v--
Each side of the resistor measure that voltage in DC the wire run from the last resistor back to your - side of battery. Maesure Voltage keeping one probe at + on battery and measure between eeach resistor for that voltage.
2006-08-26 15:06:57 · answer #2 · answered by Snaglefritz 7 · 0⤊ 0⤋
You need basically a transformer. They sell them at radio shack. It is like an adaper than you just plug into. Fairly inexpensive.
2006-08-26 16:05:13 · answer #3 · answered by Anonymous · 0⤊ 0⤋
olin1963 is right on
commosmart1 -transformers only work for AC
2006-08-26 18:11:22 · answer #4 · answered by hogie0101 4 · 0⤊ 0⤋