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6 answers

A diode or diode bridge full-wave rectifier followed by a filter is the simplest and most common AM detector. However, that circuit is phase-insenstive. Another circuit is called a "ring demodulator"; this looks af first glance like a full-wave bridge, but the diodes all face back-to-front in a ring configuration. A reference signal is applied between two opposite vertexes, and the demodulated signal is output the other two vertexes. The output will be proportional to the amplitude and the phase difference between the reference and applied signals.

In addition, any non-linear circuit can be used as an AM demodulator.

2006-08-25 15:37:56 · answer #1 · answered by gp4rts 7 · 0 0

Demodulation of an amplitude modulated signal can be accomplished in a number of ways. the simplest method is to use a diode detector or a grid leak detector. Product detectors might also be used if the frequency being tuned was carefully tuned so that the beat tone of the local oscillator was essentially zero, and that tuning did not drift off frequency. A synchronous detector is another fairly new circuit design that is quite effective in demodulation.

2006-08-29 14:20:48 · answer #2 · answered by zahbudar 6 · 0 0

I have been in comm 54 yrs. and the best I have found is to use a full wave detector like a power supply if your IF is 455 khz the ripple will be twice that. It also gives u an improvement in signal to noise ratio of 3 dB. In some ways it may be better than an improved preamp.
I think u will like it

2006-08-25 19:51:09 · answer #3 · answered by JOHNNIE B 7 · 0 0

Too complicated to explain here.
Do a google search for AM demodulation.

2006-08-25 17:29:38 · answer #4 · answered by luckyaz128 6 · 0 0

connect a diode, resistor and capacitor in series.
you got yourself a simple AM demodulator.

2006-08-25 17:37:50 · answer #5 · answered by cw 3 · 0 0

Envelope detector

2006-08-26 02:11:29 · answer #6 · answered by DoctaB01 2 · 0 0

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