2006-08-24 00:32:11 · 5 answers · asked by arshad b 2 in Science & Mathematics ➔ Engineering
The magnitude F of the centripetal force is equal to the mass m of the body times its velocity squared v 2 divided by the radius r of its path: F=mv2/r.
It is my opinion that Centrifugal force is a false force, it can only be measured at the axis point of attachment. The term is often misused.
The actual force is Centripetal force and is described in the answer above.
Yours: Grumpy
2006-08-24 01:34:47 · answer #1 · answered by Grumpy 6 · 0⤊ 0⤋
Centrifigual force technically doesn't exist. It's all based on centripital acceleration in relation to an axis and a force tangent at an angle theta with respect to the radius of movement.
2006-08-24 16:07:28 · answer #2 · answered by aadams_22 2 · 0⤊ 0⤋
I think what your talking about can be measuered as the The Burges vector (sorry I cant remember how it is spelled) and is the a mod of the normal component of the accel. forces not the speed of the end point of the rotating member.
2006-08-24 12:02:44 · answer #3 · answered by auced6371 2 · 0⤊ 0⤋
F = m * omega * r
m = mass in kilogrammes,
r = radius in meters,
omega = rotation speed expressed in radians (i.e. 1 rpm = 2 PI rads).
2006-08-24 00:47:04 · answer #4 · answered by just "JR" 7 · 0⤊ 0⤋
F=M*R*S
2006-08-24 02:14:27 · answer #5 · answered by ohwaw 4 · 0⤊ 0⤋